0.5x^2-10-6x=0

Solution for 0.5x^2-10-6x=0 equation:

0.5x^2-10-6x=0

a = 0.5; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·0.5·(-10)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{14}}{2*0.5}=\frac{6-2\sqrt{14}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{14}}{2*0.5}=\frac{6+2\sqrt{14}}{1}
$